F(x)=3x^2-9x-2

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Solution for F(x)=3x^2-9x-2 equation:



(F)=3F^2-9F-2
We move all terms to the left:
(F)-(3F^2-9F-2)=0
We get rid of parentheses
-3F^2+F+9F+2=0
We add all the numbers together, and all the variables
-3F^2+10F+2=0
a = -3; b = 10; c = +2;
Δ = b2-4ac
Δ = 102-4·(-3)·2
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{31}}{2*-3}=\frac{-10-2\sqrt{31}}{-6} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{31}}{2*-3}=\frac{-10+2\sqrt{31}}{-6} $

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